1/3x^2+20/3x=-32

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Solution for 1/3x^2+20/3x=-32 equation: 



1/3x^2+20/3x=-32

We move all terms to the left:

1/3x^2+20/3x-(-32)=0



Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R





Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

1/3x^2+20/3x+32=0

We calculate fractions

We do not support expression: x^3

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